<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-10272988</id><updated>2011-07-28T03:34:00.662-07:00</updated><title type='text'>Free IIT-JEE Mentoring</title><subtitle type='html'>Tips and tricks for JEE.
Free mentoring for JEE from IIT alumni. Join the YahooGroup!</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>21</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-10272988.post-110898315760510112</id><published>2007-12-21T02:49:00.000-08:00</published><updated>2006-03-08T17:32:08.730-08:00</updated><title type='text'>Please Support</title><summary type='text'>
 If you have any suggestions or comments about the entries, write to me at e d u j i n i @g m a i l . c o m or simply add a comment!



 Feel free to contribute to this effort. Just add a comment or write a mail to me. Rest assured, everything will be taken care of.
</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110898315760510112/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110898315760510112' title='49 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110898315760510112'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110898315760510112'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2007/12/please-support.html' title='Please Support'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>49</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-114897302027381442</id><published>2006-05-30T00:08:00.000-07:00</published><updated>2006-05-31T19:48:15.756-07:00</updated><title type='text'>Maths: Probablity Problem</title><summary type='text'>
 Two distinct numbers x and y are chosen at random from the first 30 natural numbers. What is the probability that a2 - b2 is divisible by 3?



 Well, instead of giving my clumsy solution, I'd provide the one from Karthik.



 Hint: 3|(a2 - b2)
 =&gt; 3|(a - b)(a + b)
 =&gt; 3|(a - b) or 3|(a + b) or both 



 Find the doublets (a, b) such that either a - b or a + b or both are divisible by 3.



</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/114897302027381442/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=114897302027381442' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/114897302027381442'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/114897302027381442'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2006/05/maths-probablity-problem.html' title='Maths: Probablity Problem'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-114186789756628869</id><published>2006-03-08T17:28:00.000-08:00</published><updated>2006-03-08T18:06:03.263-08:00</updated><title type='text'>Physics: Body in circular Motion</title><summary type='text'>
 Scenario: A body is moving in a circular motion with constant speed. A practical example can be -- a car moving in circular motion with constant speed. The surface of motion is horizontal.



 Problem: In which direction does the friction force apply? Assume there is only pure rolling at the contact surface.



 Solution: Have a look at the following diagram that demonstrates the change in </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/114186789756628869/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=114186789756628869' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/114186789756628869'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/114186789756628869'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2006/03/physics-body-in-circular-motion.html' title='Physics: Body in circular Motion'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-112705402917368031</id><published>2005-09-18T07:31:00.000-07:00</published><updated>2005-09-18T07:33:49.180-07:00</updated><title type='text'>New IIT-JEE format from 2006</title><summary type='text'>
 Thanks, Varun, for your mail to the group regarding the new format.



 The pattern applicable for JEE 2006 is available here
</summary><link rel='related' href='http://www.hindu.com/2005/09/18/stories/2005091803530900.htm' title='New IIT-JEE format from 2006'/><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/112705402917368031/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=112705402917368031' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112705402917368031'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112705402917368031'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/09/new-iit-jee-format-from-2006.html' title='New IIT-JEE format from 2006'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-112701699828323184</id><published>2005-09-17T21:10:00.000-07:00</published><updated>2005-09-17T21:16:38.283-07:00</updated><title type='text'>IIT JEE Format and Rules for 2006</title><summary type='text'>
 As per the latest notification from the Joint Admission Board of the IITs, the students who have passed their qualifying examination in 2005 or earlier will be permitted to appear in JEE 2006.



 A long story whose sweet and short summary is that as far as JEE 2006 is concerned, there is no change in the pattern. Not even as far as the format of the question paper is concerned. It remains same</summary><link rel='related' href='http://www.ndtv.com/template/template.asp?template=Education&amp;slug=Admission+rules%3A+Relief+for+IIT+aspirants&amp;id=17772&amp;callid=0&amp;category=National' title='IIT JEE Format and Rules for 2006'/><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/112701699828323184/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=112701699828323184' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112701699828323184'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112701699828323184'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/09/iit-jee-format-and-rules-for-2006.html' title='IIT JEE Format and Rules for 2006'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-112689702643508432</id><published>2005-09-16T11:37:00.000-07:00</published><updated>2005-09-16T12:05:29.253-07:00</updated><title type='text'>The Group made a news - A hell lot of news</title><summary type='text'>
Thanks to the dedicated team of volunteers from whom the group has become a passion and may be on way to becoming an obsession, the Free JEE Coaching Group has made a news in newspapers.



 A couple of citings are given below:



  Deccan Herald
  Digital Oppurtunity
</summary><link rel='related' href='http://www.deccanherald.com/deccanherald/aug182005/dheducation1229242005817.asp' title='The Group made a news - A hell lot of news'/><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/112689702643508432/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=112689702643508432' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112689702643508432'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112689702643508432'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/09/group-made-news-hell-lot-of-news.html' title='The Group made a news - A hell lot of news'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-112047457122519000</id><published>2005-07-04T03:53:00.000-07:00</published><updated>2005-07-04T03:56:11.233-07:00</updated><title type='text'>Back in Action - Trip to Tricks resumes</title><summary type='text'>
 I should be seen back in action starting next week. I planned last week but had to rush out for a week and this weekend too... I'd be flying away. Would be back with some more books from home.



 btw, I'm working on a (currently background) project -- putting all problems and solutions of JEE since 1982 online!!! Let me see how much success do I get in this.



 Participate in discussion forum</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/112047457122519000/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=112047457122519000' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112047457122519000'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/112047457122519000'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/07/back-in-action-trip-to-tricks-resumes.html' title='Back in Action - Trip to Tricks resumes'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110898133040015738</id><published>2005-02-21T02:17:00.000-08:00</published><updated>2005-02-21T02:22:10.403-08:00</updated><title type='text'>A Comment between T&amp;T</title><summary type='text'>
 I have been asked to write about Physics and Chemistry also. There has been a lot of Maths and also that I haven't written for about a month now. Aise to naheen chalega, boss!



 Chemistry... I admit that I don't remember even a single word of it except for the C-H-O things. Physics was my strong point and I'll write on it.



 I will start with mechanics and start with efficient use of vector</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110898133040015738/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110898133040015738' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110898133040015738'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110898133040015738'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/02/comment-between-tt.html' title='A Comment between T&amp;T'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110686134937441179</id><published>2005-01-29T11:31:00.000-08:00</published><updated>2005-01-27T13:37:11.796-08:00</updated><title type='text'>11. Tip - Don't join the most popular coaching in town</title><summary type='text'>
 I beg, DO NOT do this blunder. Well, it's under condition that that the coaching has more than 20-25 people in a batch / class. If not, you may join.



 I know if the coaching people read this, they'd be behind me. But it's a fact. More often than not they would attempt to coach more than 100 students in a class. What if you have any doubts? I bet, you won't get an answer in the class. </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110686134937441179/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110686134937441179' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110686134937441179'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110686134937441179'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/11-tip-dont-join-most-popular-coaching.html' title='11. Tip - Don&apos;t join the most popular coaching in town'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110686084912407599</id><published>2005-01-28T13:12:00.000-08:00</published><updated>2005-01-27T13:30:19.266-08:00</updated><title type='text'>10. Tip - Don't listen to what your mother says!</title><summary type='text'>
 No... I am not talking about taking food but about her worrying about your board exams or JEE screening. Believe it or not, more often than not, you will be pressurized by your mother or grandmother or some other relative to qualify JEE. If you pay more attention towards JEE, you will get scolding on not studying for your board exams. It happened to me also.



 Luckily, for me, my father </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110686084912407599/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110686084912407599' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110686084912407599'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110686084912407599'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/10-tip-dont-listen-to-what-your-mother.html' title='10. Tip - Don&apos;t listen to what your mother says!'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110657729808864215</id><published>2005-01-27T11:31:00.000-08:00</published><updated>2005-01-27T13:11:04.293-08:00</updated><title type='text'>9. Trick - Yet another multiplication trick</title><summary type='text'>
Ok, so far we've seen multiplication of numbers near powers of 10 and a generic multiplication. In this we'd see multiplication of numbers near a multiple of 10.
For example, multiplication of 37 and 39 or 42, both being near to 40 = 10*4. The key here is 4.



 Here's the full calculation:
   37  -3
   42  +2
 ----------
  39  | 6
 ----------

  =&gt; 39*4 | 6
  =&gt; 156 | 6
  =&gt; 1554</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110657729808864215/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110657729808864215' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657729808864215'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657729808864215'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/9-trick-yet-another-multiplication.html' title='9. Trick - Yet another multiplication trick'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110657351500770706</id><published>2005-01-26T11:35:00.000-08:00</published><updated>2005-01-24T06:35:33.016-08:00</updated><title type='text'>8. Trick - Squaring numbers near powers of 10</title><summary type='text'>
In this article, we shall learn about squaring numbers that are near to powers of 10 like 10, 100, 1000 etc.



The sutra for this is "Yavdunam Jaavdunikritya Varga Cha Yojayet" meaning whatever the extent of its deficiency, lessen it still further to that very extent; and also set up the square of that deficiency. 



To understand the sutra, let's take an example. We would square 96. </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110657351500770706/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110657351500770706' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657351500770706'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657351500770706'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/8-trick-squaring-numbers-near-powers.html' title='8. Trick - Squaring numbers near powers of 10'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110657208329751516</id><published>2005-01-25T11:35:00.000-08:00</published><updated>2005-01-24T05:10:17.706-08:00</updated><title type='text'>7. Trick - Division by numbers ending in 9 (Part II)</title><summary type='text'>
In the previous article, we learnt about division by numbers ending in 9. It's ok if you need exact value, like what I calculated for 1/19. But for JEE, approximate value of 1/19 = 0.05263 may do.



How do you plan to do it? Divide by 19 everytime? No... you don't need to learn tables of 19. How about dividing by 2 or 5 or such small numbers!



We will make use of previous sutra - by </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110657208329751516/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110657208329751516' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657208329751516'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110657208329751516'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/7-trick-division-by-numbers-ending-in.html' title='7. Trick - Division by numbers ending in 9 (Part II)'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110654528727971450</id><published>2005-01-24T11:35:00.000-08:00</published><updated>2005-01-23T22:43:00.850-08:00</updated><title type='text'>6. Trick - Division by numbers ending in 9 (Part I)</title><summary type='text'>
The sutra (formula) that empowers me to divide by numbers ending in 9 is again "Ekadhikena Purvena" meaning by one more than the previous one



The division can be done in two ways - by division and by multiplication .



I will take up by multiplication in this article. I will illustrate by taking two examples, 1/19 and 1/7 = 7/49



The numerator in 1/19 is 1. So, we start with 1</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110654528727971450/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110654528727971450' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654528727971450'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654528727971450'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/6-trick-division-by-numbers-ending-in.html' title='6. Trick - Division by numbers ending in 9 (Part I)'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110654668847410840</id><published>2005-01-23T22:30:00.000-08:00</published><updated>2005-01-23T22:04:48.473-08:00</updated><title type='text'>5. Trick - More Multiplication</title><summary type='text'>
This trick is an extension of the previous trick. It empowers you to multiply two numbers that can be expressed as z|y and z|(10-y).



The result of multiplication of the two numbers is z(z+1)|y(10-y)



To illustrate by an example,
37 * 33 = 3(3+1)|7*3 = 1221
141 * 149 = 14(15)|1*9 = 210|09 = 21009




Hmm... what do you say? Isn't maths really a fun! 


</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110654668847410840/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110654668847410840' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654668847410840'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654668847410840'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/5-trick-more-multiplication.html' title='5. Trick - More Multiplication'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110654580673544338</id><published>2005-01-23T21:43:00.000-08:00</published><updated>2005-01-23T21:50:06.736-08:00</updated><title type='text'>4. Trick - Squaring numbers ending in 5</title><summary type='text'>
The sutra (formula) that empowers me to do so at ease is "Ekadhikena Purevena", meaning by one more than the previous one.



To calculate square of any number ending in 5, say z5 is z(z+1)|25, ie, multiply z by z+1 and attach 25 next to it.



For example, 752 is:
752 = 7(7+1)|25 = 5625




Simple and powerful, isn't it? Now, let us see what goes behind it. It's simple algebra.
</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110654580673544338/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110654580673544338' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654580673544338'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110654580673544338'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/4-trick-squaring-numbers-ending-in-5.html' title='4. Trick - Squaring numbers ending in 5'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110650472681875156</id><published>2005-01-23T09:57:00.000-08:00</published><updated>2005-02-21T01:38:39.216-08:00</updated><title type='text'>3. Trick - Multiplication</title><summary type='text'>
Today we will learn about multiplication... once again, the same trick but with a difference.



The trick that I will tell you now will give you more power. After this, you will never need to know any table more than 5x5. I call this extension as "10's complement".



10's complement of any digit x is 10 - x. In two numbers that you are multiplying, take 10's complement of any digit greater </summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110650472681875156/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110650472681875156' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110650472681875156'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110650472681875156'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/3-trick-multiplication.html' title='3. Trick - Multiplication'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110633164267407956</id><published>2005-01-21T09:03:00.000-08:00</published><updated>2005-01-21T11:37:32.143-08:00</updated><title type='text'>2. Tip - Multiple Choice Questions</title><summary type='text'>
JEE (Joint Entrance Examination) consists of two phases: Screening, consisting of objective questions and Mains, consisting of subjective questions. Screening plays a major role in determining your entry - not only you need to be accurate, you also need to be fast.



In this article, let us see how can we avoid actual calculations and reduce time to arrive at the correct solution.



</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110633164267407956/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110633164267407956' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110633164267407956'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110633164267407956'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/2-tip-multiple-choice-questions.html' title='2. Tip - Multiple Choice Questions'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110624359689332015</id><published>2005-01-20T11:40:00.000-08:00</published><updated>2005-01-23T10:05:02.756-08:00</updated><title type='text'>1. Trick - Multiplication</title><summary type='text'>
Today we will learn about probably one of the first "Sutras" (meaning: formulas, Hindi) called Urdhva-Tiryak Sutra



In English, it means "Vertically and Crosswise". The demonstration below shows how one can shorten the calculation done:




  Conventional Method
  
  Vedic Method
  


  
  
  
  




How is it done? What's the trick? Well... nothing too great. It can be</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110624359689332015/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110624359689332015' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110624359689332015'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110624359689332015'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/1-trick-multiplication.html' title='1. Trick - Multiplication'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110633664301221683</id><published>2005-01-20T10:20:00.000-08:00</published><updated>2005-09-16T12:44:21.603-07:00</updated><title type='text'>Free-JEE Yahoo Group</title><summary type='text'>
Courtsey Rambo, an IITM alumnus, a Yahoo group has been created towards Free-JEE education. Click here to learn more about it.
</summary><link rel='related' href='http://groups.yahoo.com/group/IITGlobal_Free_JEE_Coaching' title='Free-JEE Yahoo Group'/><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110633664301221683/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110633664301221683' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110633664301221683'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110633664301221683'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/free-jee-yahoo-group.html' title='Free-JEE Yahoo Group'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-10272988.post-110620459269313020</id><published>2005-01-19T23:56:00.000-08:00</published><updated>2005-01-27T07:53:11.896-08:00</updated><title type='text'>Introduction</title><summary type='text'>
I am creating this blog with an intention to provide tips and tricks for all Indian Institute of Technology aspirants.



Given below is the list of all IITs (in alphabetical order):


  IIT Bombay
  IIT Delhi
  IIT Guwahati
  IIT Kanpur
  IIT Kharagpur
  IIT Madras
  IIT Roorkee



Below is the list of the website of their alumni networks:


  IIT Bombay
  IIT Delhi
  IIT</summary><link rel='replies' type='application/atom+xml' href='http://freejee.blogspot.com/feeds/110620459269313020/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=10272988&amp;postID=110620459269313020' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110620459269313020'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/10272988/posts/default/110620459269313020'/><link rel='alternate' type='text/html' href='http://freejee.blogspot.com/2005/01/introduction.html' title='Introduction'/><author><name>Gaurav Vaish</name><uri>http://www.blogger.com/profile/06113293459233077128</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='22' src='http://bp3.blogger.com/_-xY-nqOFQDM/SBodI9uUfXI/AAAAAAAABJg/Iu9yItLFJV4/S220/01.jpg'/></author><thr:total>0</thr:total></entry></feed>
